Question
Given a non-negative number represented as an array of digits, plus one to the number.
The digits are stored such that the most significant digit is at the head of the list.
Solution
Result: Accepted Time: x ms
Here should be some explanations.
int* plusOne(int* digits, int digitsSize, int* returnSize) {
int carry = 1;
int len = 0,tmp;
int * ans = malloc(sizeof(int)*(digitsSize+4));
int * ary = malloc(sizeof(int)*(digitsSize+4));
for(tmp = 0; tmp < digitsSize;tmp++)
ans[tmp] = digits[digitsSize-tmp -1];
while(carry || len < digitsSize)
{
tmp = (carry + ans[len]);
carry = tmp/10;
ary[len++] = tmp%10;
}
for(tmp = 0; tmp < len;tmp++)
ans[tmp] = ary[len-tmp -1];
free(ary);
*returnSize = len;
return ans;
}
Complexity Analytics
- Time Complexity:
- Space Complexity: