Question
The count-and-say sequence is the sequence of integers beginning as follows:
1, 11, 21, 1211, 111221, ...
`
1
is read off as"one 1"
or11
.
11
is read off as"two 1s"
or21
.
21
is read off as"one 2"
, then"one 1"
or1211
.Given an integer , generate the sequence.
Note: The sequence of integers will be represented as a string.
Solution
Result: Accepted Time: 12ms
Here should be some explanations.
vector<string> say;
char buffer[1024 * 256];
char buf[1024*256];
int cnt=0;
class Solution {
public:
Solution(){
if(cnt) return;
say.push_back("1");cnt = 1;
}
string countAndSay(int n) {
return get_nth(n);
}
string get_nth(int n)
{
if(n < cnt)
return say[n];
const char* tmp = say[cnt-1].c_str();
char cur = tmp[0];
int len = say[cnt-1].size();
int num = 0;
int idx = 0;
buf[0] = 0;
while(cnt < n)
{
while(idx <= len)
{
if(cur == tmp[idx++])
num++;
else
{
sprintf(buffer,"%s%d%c",buf,num,cur);
strcpy(buf,buffer);
cur = tmp[idx-1];
num = 1;
}
}
say.push_back(string(buffer));
tmp = say[cnt++].c_str();
buf[0]=0;
cur = tmp[0];
idx = 0;
num = 0;
len = say[cnt -1].size();
}
return say[n-1];
}
};
Complexity Analytics
- Time Complexity:
- Space Complexity: