Question
Given two strings s and t, write a function to determine if t is an anagram of s.
For example,
s = "anagram"
, t = "nagaram"
, return true
.
s = "rat"
, t = "car"
, return false
.
Note:
You may assume the string contains only lowercase alphabets.
Follow up:
What if the inputs contain unicode characters? How would you adapt your solution to such case?
Solution
Result: Accepted Time: 0 ms
Here should be some explanations.
bool isAnagram(char* s, char* t) {
int have[256]={0};
while(*s) have[*(s++)]++;
while(*t) have[*(t++)]--;
for(char tmp = 'a';tmp <= 'z'; ++tmp)
if(have[tmp])
return false;
return true;
}
Complexity Analytics
- Time Complexity:
- Space Complexity: