Question
Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.
For example, given array S = {-1 2 1 -4}, and target = 1. The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
Solution
Result: Accepted Time: 28ms
Here should be some explanations.
class Solution {
inline int iabs(int a)
{
return a > 0 ? a : -a;
}
public:
int threeSumClosest(vector<int>& nums, int target) {
sort(nums.begin(),nums.end());
const int len = nums.size();
int ret = 0x3fffffff;
for(int i = 0; i < len - 2; i++)
{
int low = i + 1, up = len - 1, diff = nums[i] - target;
while(low < up)
{
int tmp = nums[low] + nums[up] + diff ;
if(tmp > 0)
up --;
else
low ++;
if(iabs(tmp) < iabs(ret-target))
ret = tmp + target;
}
}
return ret;
}
};
Complexity Analytics
- Time Complexity:
- Space Complexity: