Question
Given a singly linked list L: L0→L1→…→Ln-1→Ln,
reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→…
You must do this in-place without altering the nodes’ values.
For example,
Given
{1,2,3,4}
, reorder it to{1,4,2,3}
.
Solution
Result: Accepted Time: 16 ms
Here should be some explanations.
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* struct ListNode *next;
* };
*/
struct ListNode * reverse(struct ListNode * head)
{
struct ListNode Head,*tmp;
Head.next = NULL;
while(head)
{
tmp = head;
head = head->next;
tmp->next = Head.next;
Head.next = tmp;
}
return Head.next;
}
void reorderList(struct ListNode* head) {
struct ListNode Head,*fast,*slow,*last;
Head.next = head;
last = &Head;
slow = fast = head;
while(fast && fast->next)
{
fast = fast->next->next;
slow = slow->next;
}
if(fast)
{
fast = slow;
slow = slow->next;
fast->next = NULL;
}
slow = reverse(slow);
while(slow)
{
last->next = head;
last = head;
head = head->next;
last->next = slow;
last = slow;
slow = slow ->next;
}
last->next = fast;
}
Complexity Analytics
- Time Complexity:
- Space Complexity: