Question
Rotate an array of n elements to the right by k steps.
For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4].
Note:
Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem.
Hint:
Could you do it in-place with O(1) extra space?
Solution
Result: Accepted Time: 24 ms
Here should be some explanations.
class Solution {
void reverse(vector<int>& nums,int i,int k)
{
int tmp ;
while(i<k)
{
tmp = nums[i];
nums[i++] = nums[k];
nums[k--] = tmp;
}
}
public:
void rotate(vector<int>& nums, int k) {
k = k%(nums.size());
if(!k) return ;
reverse(nums,0,nums.size()-k-1);
reverse(nums,nums.size()-k,nums.size()-1);
reverse(nums,0,nums.size()-1);
}
};
Complexity Analytics
- Time Complexity:
- Space Complexity: