Question
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.
- push(x) – Push element x onto stack.
- pop() – Removes the element on top of the stack.
- top() – Get the top element.
- getMin() – Retrieve the minimum element in the stack.
Example:
MinStack minStack = new MinStack(); minStack.push(-2); minStack.push(0); minStack.push(-3); minStack.getMin(); --> Returns -3. minStack.pop(); minStack.top(); --> Returns 0. minStack.getMin(); --> Returns -2.
Solution
Result: Accepted Time: 28 ms
Here should be some explanations.
class MinStack {
stack<int> sta;
stack<int> min_sta;
public:
void push(int x) {
sta.push(x);
if(min_sta.empty())
{
min_sta.push(x);
return;
}
min_sta.push(min(min_sta.top(),x));
}
void pop() {
sta.pop();
min_sta.pop();
}
int top() {
return sta.top();
}
int getMin() {
return min_sta.top();
}
};
Complexity Analytics
- Time Complexity:
- Space Complexity: